a,\(\sqrt{5X^2+X+3}-2\sqrt{5x-1}+X^2-3X+3=0\)
b,\(^{X^2-X-4+3X\sqrt{5-3X^2}=0}\)
giải phương trình sau:
a) \(4x^2+\left(8x-4\right).\sqrt{x}-1=3x+2\sqrt{2x^2+5x-3}\)
b) \(8x^3-36x^2+\left(1-3x\right)\sqrt{3x-2}-3\sqrt{3x-2}+63x-32=0\)
c) \(2\sqrt[3]{3x-2}-3\sqrt{6-5x}+16=0\)
d) \(\sqrt[3]{x+6}-2\sqrt{x-1}=4-x^2\)
Giải các phương trình sau:
1) \(\sqrt{3x^2+5x+8}-\sqrt{3x^2+5x+1}=1\)
2) \(x^2-2x-12+4\sqrt{\left(4-x\right)\left(2+x\right)}=0\)
3) \(3\sqrt{x}+\dfrac{3}{2\sqrt{x}}=2x+\dfrac{1}{2x}-7\)
4) \(\sqrt{x}-\dfrac{4}{\sqrt{x+2}}+\sqrt{x+2}=0\)
5)\(\left(x-7\right)\sqrt{\dfrac{x+3}{x-7}}=x+4\)
6) \(2\sqrt{x-4}+\sqrt{x-1}=\sqrt{2x-3}+\sqrt{4x-16}\)
7) \(\sqrt{x+2\sqrt{x-1}}+\sqrt{x-2\sqrt{x-1}}=\dfrac{x+3}{2}\)
Giúp mình với ajk, mink đang cần gấp
\(a,2x^2-9x+3+\sqrt{3x^2-7x+1}=0\)
b)\(\sqrt{x+2}+\sqrt{3-x}=x^3+x^2-4x-1\)
c)\(\text{4x^3-9x^2+7x-(3x-1)\sqrt{3x-2}=0}\)
d)\(2\sqrt{x-1}+\sqrt{5x-1}=x^2+1\)
e)\(\sqrt{x+2}+\sqrt{5x+6}+2\sqrt{8x+9}=4x^2\)
f)\(3x^2-x+3=\sqrt{3x+1}+\sqrt{5x+4}\)
bài 1 : giải các phương trình sau
a / \(\sqrt{3x+10}-\sqrt{x+2}=\sqrt{3x}-2\)
b/ \(x^2-3x+\sqrt{x^2-3x+2}=10\)
c/ 3\(\sqrt{x^2-5x+10}=5x-x^2\)
d/ (x+4)(x-4)+3\(\sqrt{x^2-x+3}+5=0\)
Giải các pt sau:
a) \(\sqrt{x+8}+\frac{9x}{\sqrt{x+8}}-6\sqrt{x}=0\)
b) \(x^4-2x^3+\sqrt{2x^3+x^2+2}-2=0\)
c) \(3x\sqrt[3]{x+7}\left(x+\sqrt[3]{x+7}\right)=7x^3+12x^2+5x-6\)
d) \(4x^2+\left(8x-4\right)\sqrt{x}-1=3x+2\sqrt{2x^2+5x-3}\)
e) \(16x^2+19x+7+4\sqrt{-3x^2+5x+2}=\left(8x+2\right)\left(\sqrt{2-x}+2\sqrt{3x+1}\right)\)
f) \(\left(5x+8\right)\sqrt{2x-1}+7x\sqrt{x+3}=9x+8-\left(x+26\right)\sqrt{x-1}\)
g) \(\sqrt[3]{3x+1}+\sqrt[3]{5-x}+\sqrt[3]{2x-9}-\sqrt[3]{4x-3}=0\)
Hung nguyen, Trần Thanh Phương, Sky SơnTùng, @tth_new, @Nguyễn Việt Lâm, @Akai Haruma, @No choice teen
help me, pleaseee
Cần gấp lắm ạ!
giai cac phuong trinh
a)\(2x^4+5x^3+x^2+5x+2=0\)
b)\(\sqrt{x-1}-\sqrt[3]{2-x}=1\)
c)\(x-\sqrt{x}+1=\sqrt{2x^2-30x+2}\)
d)\(2x^2+3x+7=\left(x-5\right)\sqrt{2x^2+1}\)
e)\(\sqrt{x-2}+\sqrt{4-x}=2x^2-5x-1\)
giải pt
a) \(\sqrt[3]{x+6}+\sqrt{x-1}=x^2-1\)
b) \(\sqrt[3]{x-9}+2x^2+3x=\sqrt{5x-1}+1\)
c) \(\sqrt{3x+1}-\sqrt{6-x}+3x^2-14x-8=0\)
d) \(\sqrt{x+1}-2\sqrt{4-x}=\frac{5\left(x-3\right)}{\sqrt{2x^2+18}}\)
e) \(x^3+5x^2+6x=\left(x+2\right)\left(\sqrt{2x+2}+\sqrt{5-x}\right)\)
a. \(2x^2-8x-3\sqrt{x^2-4x-5}=12\)
b. \(\left(x-3\right)\left(x+2\right)-3\sqrt{x^2-x+1}+9=0\)
c. 12\(-\sqrt{4-3x}=|3x-4|\)
d. \(\sqrt{3x-2}+\sqrt{x-1}=4x-9+2\sqrt{3x^2-5x+2}\)
1. \(2^3\sqrt{3x-2}+3\sqrt{6-5x}-8=0\)
2. \(\sqrt{3x+1}-\sqrt{6-x}+3x^2-14x-8=0\)
3. \(\sqrt{x^2+12}+5=3x+\sqrt{x^2+5}\)
Bài 2:
ĐKXĐ: $6\geq x\geq \frac{-1}{3}$
PT $\Leftrightarrow (\sqrt{3x+1}-4)+(1-\sqrt{6-x})+(3x^2-14x-5)=0$
$\Leftrightarrow \frac{3(x-5)}{\sqrt{3x+1}+4}+\frac{x-5}{\sqrt{6-x}+1}+(3x+1)(x-5)=0$
$\Leftrightarrow (x-5)\left[\frac{3}{\sqrt{3x+1}+4}+\frac{1}{\sqrt{6-x}+1}+(3x+1)\right]=0$
Với $x$ thuộc đkxđ, dễ thấy biểu thức trong ngoặc vuông $>0$
$\Rightarrow x-5=0$
$\Leftrightarrow x=5$
Bài 3:
PT $3x=\sqrt{x^2+12}-\sqrt{x^2+5}+5>0$
$\Rightarrow x>0$
Lại có:
PT $\Leftrightarrow \sqrt{x^2+12}-4=3(x-2)+(\sqrt{x^2+5}-3)$
$\Leftrightarrow \frac{x^2-4}{\sqrt{x^2+12}+4}=3(x-2)+\frac{x^2-4}{\sqrt{x^2+5}+3}$
$\Leftrightarrow (x-2)\left[\frac{x+2}{\sqrt{x^2+12}+4}-3-\frac{x+2}{\sqrt{x^2+5}+3}\right]=0$
Với $x>0$, dễ thấy:
$\frac{x+2}{\sqrt{x^2+5}+3}+3>\frac{x+2}{\sqrt{x^2+12}+4}$ nên biểu thức trong ngoặc vuông âm.
Do đó $x-2=0\Leftrightarrow x=2$ (tm)
Bài 1:
Đặt $\sqrt[3]{3x-2}=a; \sqrt{6-5x}=b$ với $b\geq 0$. Khi đó pt trở thành:
\(\left\{\begin{matrix}
2a+3b=8\\
5a^3+3b^2=8\end{matrix}\right.\Rightarrow 5a^3+3(\frac{8-2a}{3})^2=8\)
\(\Leftrightarrow 15a^3+(8-2a)^2=24\)
\(\Leftrightarrow 15a^3+4a^2-32a+40=0\)
\(\Leftrightarrow 15a^2(a+2)-26a(a+2)+20(a+2)=0\)
$\Leftrightarrow (a+2)(15a^2-26a+20)=0$
Dễ thấy $15a^2-26a+20>0$ nên $a+2=0$
$\Leftrightarrow a=-2$
$\Rightarrow b=4$
$\Rightarrow x=-2$